Categories Geometry Perimeter and Volume What is going on in these volume calculations? Post author By mpershan Post date October 12, 2015 6 Comments on What is going on in these volume calculations? I’m stumped. Ideas? Share this:EmailPrint ← Using Math Mistakes in Whole-Group Discussions → How Sets of Class Work Change the Conversation 6 replies on “What is going on in these volume calculations?” Well, for the first one I added the three side lengths, doubled the result, and subtracted the unit volume, as I knew it involved volume. The second one I couldn’t get anywhere with! Seriously, though, the marking scheme should go like this: Max 3 less 2 for not showing any working less 2 for getting the wrong numerical answer less 1 for not getting the units right Total score -2 I suspect that the author never played with blocks in K-2 Not very likely, but possibly mistaken perimeters? My guess is perimeter of base, plus height. Where they may have made different choices of which side should be the height… sometimes reusing one of the sides of the base, oops. Hm. 2*(7+4) + 4 seems right for the second one, and the units are even correct for that. 2*(6+5) + 3 would make sense but that’s only 25 feet, not 27. Still, seems like a reasonable idea of what the student was trying to do? Maybe? This is sort of similar to the “length plus girth” measurement that shipping companies use to figure out whether your box is “large” and has to pay more, right? Except there the length is always the longest side and the girth is the perimeter perpendicular to that. I think. Best guess… student attempted to find the perimeter of the shaded areas and made computational errors each time. Hmm, how long before this was area and perimeter taught? Were other 3D volumes taught at the same time? Was the ‘prism’ concept only introduced through paper or through 3D models, as well? Were students taught via equations or taught by building up ‘unit block’ concept? Having said that, my first thought about the second shape (7x4x4) was that the equation ‘half of base times height’. Then, either the shape looks ‘flat’ enough that the base is just the width (7+4) or the simply forgot that ‘base’ in this case means width ‘times’ length rather than ‘plus’. How about 7^2 + 4^3 = 7*2+4*3 for the 2nd one? Comments are closed.